Question

paid office rent for the month of March 19 of 7 30000 and also cleared outstanding rent on 02-07-19 through
cheque of HSBC #153001. Allocate Rent of ? 20000 for Mumbai Branch and ? 10000 for Kolkata Branch
respectively.
Cleared the Bill No. SRE/18-19/789 of S. R. Enterprises through the cheque of HSBC #153002 on 04-07-19
Received a dividend on NSC of * 100,000/- in cheque of Canara Bank #174001 and deposited the same in
HSBC Bank on 04-07-19
* 20000/- withdrawn from HSBC (Cheque no. #153003) for office use on 05-07-19.
Received a cheque of 20000/- from Crabtree and deposited the same in HSBC (Cheque #1657001 of SCB
on 07-07-19. Bill No.-INV/312/18-19.
- Salary due to a staff of 10000/- for the month March'19 as on 08-07-19.
B. Paid 80% of the Bill No. SRE/18-19/701 to S. R. Enterprises in full and final settlement through the cheque
of HSBC #153004 as on 10-07-19.
9. Received 8000/- in cheque # 165700 of SCB from Crabtree in full and final settlement of his account on
12-07-19 and deposited the same in HSBC Bank.
10. Transfer 100,000/- from Axis Bank to HSBC as on 27-07-19.
11. Withdrew * 40000/ - from HSBC for personal expense of the owner. (Cheque # 153005) as on 28-07-19.
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Answer 1

Answer:

ANSWER EXPLANATION: There are two ways to solve this question. The faster way is to multiply each side of the given equation by ax−2 (so you can get rid of the fraction). When you multiply each side by ax−2, you should have:

24x2+25x−47=(−8x−3)(ax−2)−53

You should then multiply (−8x−3) and (ax−2) using FOIL.

24x2+25x−47=−8ax2−3ax+16x+6−53

Then, reduce on the right side of the equation

24x2+25x−47=−8ax2−3ax+16x−47

Since the coefficients of the x2-term have to be equal on both sides of the equation, −8a=24, or a=−3.

The other option which is longer and more tedious is to attempt to plug in all of the answer choices for a and see which answer choice makes both sides of the equation equal. Again, this is the longer option, and