Question

pair of equation by elimination method 2x+y=5, 3x+2y=8​

Answer 1

Step-by-step explanation:

6x + 3y=15

6x + 4y= 16

-1y= -1

ans = 1

Answer 2

${ \rm{ \large{the \: given \: pair \: are \longrightarrow}}}$

${ \rm{2x + y = 5 \: \longrightarrow(i)}}$

${ \rm{3x +2 y = 8 \: \longrightarrow(ii)}}$

${ \rm { \large{taking \: eqa.(i)}}}$

${ \rm{2x + y = 5 \: \longrightarrow(i)}}$

${ \rm{ \implies y = 5 - 2x }}$

${ \rm{ \large{ putting \: the \: value \: of \: y \: in \: eqa.(ii)}}}$

${ \rm{3x +2 y = 8 \: \longrightarrow(ii)}}$

${ \rm{ \implies 3x + 2(5 - 2x) = 8}}$

${ \rm{ \implies 3x + 10 - 4x = 8}}$

${ \rm{ \implies - x = 8 - 10}}$

${ \rm{ \implies - x = - 2}}$

${ \rm{ \implies x = 2}}$

${ \rm{ \therefore x =2}}$

${ \rm{ \large{ putting \: the \: value \: of \: x\: in \: eqa.(i)}}}$

${ \rm{3x +2 y = 8 \: \longrightarrow(ii)}}$

${ \rm{ \implies3(2)+2 y = 8 \: }}$

${ \rm{ \implies6+2 y = 8 \: }}$

${ \rm{ \implies2 y = 8 - 6\: }}$

${ \rm{ \implies y = \dfrac{2}{2} \: = 1 }}$

${ \rm{ \therefore y = 1}}$

${ \tt{ \large{so \: the \: value \: is = }}}$

${ \tt{ \large{ x = 2}}}$

${ \tt{ \large{ y = 1}}}$