Pair of integer whose product is -36 and. Difference is 15
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let the integers be x and y
ATQ
xy=-36
so y=-36/x
x-y=15
put the value of y in x
x-(-36/x) =15
x+36/x=15
x^2+36=15x
x^2-15x+36=0
x^2-12x-3x+36=0
x(x-12) -3(x-12) =0
(x-3) (x-12) =0
x=3
x=12
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