pair of linear equation 2x+4y=8 and x+2y=4 has how many solution
Answers
Answered by
1
Answer:
infinite solution ..........
Answered by
6
Step-by-step explanation:
Option ( c ) is correct.
Explanation :
Given equations are
2x + 4y = 8
=> 2x + 4y - 8 = 0 ---( 1 )
x + 2y - 4 = 0 ---( 2 )
Compare these with
a1x + b1y + c1 = 0 and
a2x + b2y + c2 = 0 we get
a1 = 2 , b1 = 4 , c1 = -8
a2 = 1 , b2 = 2 , c2 = -4
Now ,
a1/a2 = 2/1 = 2 ,
b1/b2 = 4/2 = 2 ,
c1/c2 = ( -8 )/( -4 ) = 2
Therefore ,
a1/a2 = b1/b2 = c1/c2 = 2
So, the pair of linear equations
is not consistent .
They have infinitely many solutions.
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