Question

pair of linear equation 2x+4y=8 and x+2y=4 has how many solution​

Answer 1

Answer:

infinite solution ..........

Answer 2

Step-by-step explanation:

Option ( c ) is correct.

Explanation :

Given equations are

2x + 4y = 8

=> 2x + 4y - 8 = 0 ---( 1 )

x + 2y - 4 = 0 ---( 2 )

Compare these with

a1x + b1y + c1 = 0 and

a2x + b2y + c2 = 0 we get

a1 = 2 , b1 = 4 , c1 = -8

a2 = 1 , b2 = 2 , c2 = -4

Now ,

a1/a2 = 2/1 = 2 ,

b1/b2 = 4/2 = 2 ,

c1/c2 = ( -8 )/( -4 ) = 2

Therefore ,

a1/a2 = b1/b2 = c1/c2 = 2

So, the pair of linear equations

is not consistent .

They have infinitely many solutions.

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