Pair of linear equations 3x+4y= 11 and 6x+8y= 22 is
intersecting, parallel and coincident?
Answers
Concept Understanding :-
The linear equations is a equation which having highest power of degree 1
The equation can be expressed as ,
ax + by + c = 0
For finding lines
Compare the equation with a1x+b1y + c1 and
a2x +b2y + c2 = 0
a1/a2 ≠ b1/b2 forms intersecting lines it means they are having unique solution
a1/a2 = b1/b2 = c1/c2 forms coincident lines it means they are having infinite solution
a1/a2 = b1/b2 ≠ c1/c2 forms parallel lines it means they are having no solution.
Solution :-
Given equation
3x + 4y = 11 , 3x + 4y - 11 = 0
6x + 8y = 22 , 6x + 8y -22 = 0
Comparing the given equation with
a1x + b1y + c1 =0 and a2x + b2x + c2 = 0
Therefore ,
a1 = 3 , b1 = 4 , c1 = -11
a2 = 6 , b2 = 8 , c2 = -22
Now,
3/6 = 4/ 8 = -11/-22
1/2 = 1/2 = 1/2
Hence, It forms parallel lines
The linear equations is a equation which having highest power of degree 1
The equation can be expressed as ,
ax + by + c = 0
For finding lines
Compare the equation with a1x+b1y + c1 and
a2x +b2y + c2 = 0
a1/a2 ≠ b1/b2 forms intersecting lines it means they are having unique solution
a1/a2 = b1/b2 = c1/c2 forms coincident lines it means they are having infinite solution
a1/a2 = b1/b2 ≠ c1/c2 forms parallel lines it means they are having no solution.
Given equation
3x + 4y = 11 , 3x + 4y - 11 = 0
6x + 8y = 22 , 6x + 8y -22 = 0
Comparing the given equation with
a1x + b1y + c1 =0 and a2x + b2x + c2 = 0
Therefore ,
a1 = 3 , b1 = 4 , c1 = -11
a2 = 6 , b2 = 8 , c2 = -22
Now,
3/6 = 4/ 8 = -11/-22
1/2 = 1/2 = 1/2