Question

pair of two different dice is thrown once. Find the probability of getting:
)
a total of 9.
(ii)
an even prime number as sum.​

Answer 1

Answer:

1)4÷36=1/9=0.1111

2)0/36=0

Answer 2

Answer:

(i)1/9

(ii)1/36

Step-by-step explanation:

(i) s={(3,6)(6,3)(4,5)(5,4)}

P(E)= 4/36=1/9

36 as there are 36 possibilities in total...

(ii)s={(1,1)

P(E)= 1/36

hope this helps buddy

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