Math, asked by akshayaa952, 1 month ago

pairs with less difference among equal sum, will have the greater product consider 23×37 and 24×36.Both pairs have the sum 60their difference
37-23=14,36-24=12
so
23×37/difference =14
24×36/difference =12
(i. e 24×36 is greater then 23×31)
using this, find out the larger product of each pair below, without actwal multiplication.
a)35×65,34×66
b)112×88,114×86

Answers

Answered by pulakmath007
2

SOLUTION

TO DETERMINE

The larger product of each pair below, without actual multiplication.

a) 35 × 65 , 34 × 66

b) 112 × 88 , 114 × 86

EVALUATION

(a) Here the given pairs are 35 × 65 , 34 × 66

Sum of each pair = 100

Now

For 35 × 65 the difference

= 65 - 35

= 30

For 34 × 66 the difference

= 66 - 34

= 32

Since 32 > 30

So 34 × 66 is greater 35 × 6

(b) Here the given pairs are 112 × 88 , 114 × 86

Sum of each pair = 200

Now

For 112 × 88 the difference

= 112 - 88

= 24

For 114 × 86 the difference

= 114 - 86

= 28

Since 28 > 24

So 114 × 86 is greater 112 × 88

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