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Calculate the oxidation number of 'Cr'
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Explanation:
This is the dichromate ion,
C
r
2
O
2
−
7
.
Oxygen is more electronegative than chromium, so it'll take its usual
−
2
charge here. There are seven oxygen atoms, so the total charge is
−
2
⋅
7
=
−
14
.
Let
x
be the oxidation number of two chromium atoms. So, we got:
x
+
(
−
14
)
=
−
2
x
−
14
=
−
2
x
=
12
So, two chromium atoms have a total oxidation number of
+
12
. Since one is not more electronegative than the other, we can divide the number by two to get one chromium's oxidation number.
12
2
=
6
So, a chromium atom here has an oxidation number of
+
6
.
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