Question

pankaj got 15 mark less than charu ,charu got 5 mark more than rohit total =112

Answer 1

Let the marks obtained by Rohit be x

So According to the question,

Charu's marks = Rohit + 5

=> Charu = x + 5

Now Pankaj's marks = Charu - 15

=> Pankaj = x + 5 - 15

=> Pankaj = x - 10

Now given total = 112

=> Pankaj + Charu + Rohit = 112

=> x - 10 + x + 5 + x = 112

=> 3x - 5 = 112

=> 3x = 112 + 5

=> 3x = 117

=> x = 117/3

=> x = 39

Since x = Rohit,

=> Rohit = 39

And, Charu = x + 5

=> Charu = 39 + 5

=> Charu = 44

And Pankaj = x - 10

=> Pankaj = 39 - 10

=> Pankaj = 29 marks


So,

Rohit = 39
Charu = 44
Pankaj = 29

Hope it helps dear friend ☺️✌️

Answer 2

We can easily find out that we can relate the marks of Pankaj as well as of Charu with Rohit.

Therefore we assume the marks of Rohit be a variable like ' x '.

Marks of Rohit = x

Accordingly,

Marks of Charu = ( x + 5 )
Marks of Pankaj = ( x + 5 ) - 15 = x + 5 - 15 = ( x - 10 )

Now,

It is given that the sum of the marks of these three is 112.

So,

( x ) + ( x + 5 ) + ( x - 10 ) = 112
x + x + 5 + x - 10 = 112
3x - 5 = 112
3x = 112 + 5
3x = 117
x = 117 / 3
x = 39

Therefore,
Marks of Rohit = x = 39
Marks of Charu = x + 5 = 44
Marks of Pankaj = x - 10 = 29