Question

Pankaj invested 2.000 at
12 1/2% for the period 5th March, 2002 to 10 October, 2002. How much
amount did he get back at the end of the period ?​

Answer 1

➤ Correct Question :-

Pankaj invested 2,000 at 12½% for the period from 5th march 2002 to 10th pctober 2002. How much amount did he get back at the end of the period ?

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➤ Given :-

Principle :- ₹2000

Rate of interest :- 12½%

Time :- 5 March to 10 October = 0.6 years

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➤ To Find :-

Total amount he receives at end of the period

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➤ Formula required :-

${\large \tt \dashrightarrow \orange{\boxed{\tt \gray{Simple \: Interest + Principle}}}}$

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★ How to do :-

Here, we are given that a boy invests 2000 rupees at 12½% and the time is from 5th march 2002 to 10th october 2002 i.e, 219 days. As we know that to calculate the total amount or simple interest always the time should be in years. So, we can write the years as 219 divided by 365, because the total never of days in a year is 365. Next, if we simplify that we will obtain with the result as 0.6 years. Then, we can calculate the simple interest by multiplying the principle, rate and time and then multiply by 100. Finally, we can find the total amount by using the given formula.

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➤ Solution :-

Simple Interest :-

${\tt \leadsto \dfrac{2000 \times 25 \times 0.6}{100 \times 2}}$

${\tt \leadsto \dfrac{\cancel{2000} \times 25 \times 0.6}{\cancel{100} \times 2} = \dfrac{20 \times 25 \times 0.6}{2}}$

${\tt \leadsto \dfrac{20 \times 15}{2} = \dfrac{300}{2}}$

${\tt \leadsto \cancel \dfrac{300}{2} = \boxed{\tt 150}}$

Total amount :-

${\tt \leadsto 150 + 2000}$

${\tt \leadsto \boxed{ \tt Rs \: \: 2150}}$

$\Huge\therefore$ Pankaj will receive ₹2150 at end of the period.

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$\dashrightarrow$ Some related formulas :-

${\tt \longrightarrow \boxed{\tt Simple \: Interest = \dfrac{P \times R \times T}{100}}}$

${\tt \longrightarrow \boxed{\tt Principle = \dfrac{SI \times 100}{R \times T}}}$

${\tt \longrightarrow \boxed{\tt Rate \: of \: Interest = \dfrac{SI \times 100}{P \times T}}}$

${\tt \longrightarrow \boxed{\tt Time = \dfrac{SI \times 100}{P \times R}}}$

Answer 2

Answer:

answer is 2150

Step-by-step explanation:

hope it helps