paper bhuit. aaasan ayyaaaa mera maths kka
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∴ 4(2x + 6) = x(x + 6)
∴ 8x + 24 = x2 + 6x
∴ x2 + 6x – 8x – 24 = 0
∴ x2 – 2x – 24 = 0
∴ x2 – 6x + 4x – 24 = 0
∴ x(x – 6)+ 4(x – 6) = 0
∴ (x – 6) (x + 4) = 0
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Step-by-step explanation:
∴ 4(2x + 6) = x(x + 6)
∴ 8x + 24 = x2 + 6x
∴ x2 + 6x – 8x – 24 = 0
∴ x2 – 2x – 24 = 0
∴ x2 – 6x + 4x – 24 = 0
∴ x(x – 6)+ 4(x – 6) = 0
∴ (x – 6) (x + 4) = 0
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