paper is the form of rectangle ABCD in which a b 20 CM and BC 14 cm a semicircle portion on which BC as diameter is cut off find the area of remaining part
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answer is:
area of rectangle=length×breadth
=20cm×14cm
=280cm^
now,
radius of circle=BC/2
=14cm/2
=7cm
area=πr^
=22/7×7cm×7cm
=22×1cm×7cm
=154cm^
area of remaining part=280cm^-154cm^
=126cm^.
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