Question

papergrid Date: 11 density of NaCl = 2.1 g/cc, &a = 562m Z=4 1 find NA​

Answer 1

Explanation:

Given that the distance between Na

+

and Cl

−

ion is 281 pm.

So, a(edgelength)=2×281=562 pm= 562×10

−10

cm.

The formula for density is given below:

d=

N

A

a

3

zM

, where z is the number of atoms in a lattice type.

Substituting the values, we get

N

A

×(562×10

−10

)

3

4×58.5

=2.165 g/cc ⟹N

A

=6.089×10

23

mol

−1