PAQ is a tangent to circle with centre O, at a point A on it. AB is a chord such that ∠BAQ = x∘(x < 90). C is a point on the major
arc AB such that ∠ACB = y∘. If ∠ABO = 32∘, then the value of x + y is:
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Answer:
∠BAP=75
∘
∠OAP=90
∘
∴∠OAB=90
∘
−75
∘
=15
∘
So, ∠AOB=180
∘
−2(15
∘
)=150
∘
∴Exterior∠AOB=360
∘
−150
∘
=210
∘
So, ∠ACB=
2
1
(210
∘
)=105
∘
[Angle subtended by an arc at the centre is double than the angle subtended by it at the remaining part of the circle]
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