Hindi, asked by manojsingh001000, 7 hours ago

पर 3. 'सर्पदंश' पाठ के आधार पर प्रधान द्वारा गोकुल किये गए अत्याचार को अपने शब्दों में लिखो|​

Answers

Answered by reshmaakkar55
1

Answer:

Given that, ABCD is a rhombus.

Hence, AB=BC=CD=DA 

In ΔABC and ΔADC,

AB=CD

BC=DA

and 

∠ABC=∠ADC            [Opposite angles of a rhombus are equal]

Hence, by SAS congruence criterion,

ΔABC≅ΔADC 

∴ ∠1=∠4                [cpct]

and ∠3=∠2              [cpct]

Also,

AB=BC

∴ ΔABC is isosceles 

Hence, ∠1=∠3    [Angles opposite to equal sides of a triangle are equal]

∴ ∠1=∠2=∠3=∠4

Hence, it is proved that AC bisects ∠BCD and ∠BAD.

Similarly, BD will bisect ∠ABC and ∠ADC

Explanation:

Given that, ABCD is a rhombus.

Hence, AB=BC=CD=DA 

In ΔABC and ΔADC,

AB=CD

BC=DA

and 

∠ABC=∠ADC            [Opposite angles of a rhombus are equal]

Hence, by SAS congruence criterion,

ΔABC≅ΔADC 

∴ ∠1=∠4                [cpct]

and ∠3=∠2              [cpct]

Also,

AB=BC

∴ ΔABC is isosceles 

Hence, ∠1=∠3    [Angles opposite to equal sides of a triangle are equal]

∴ ∠1=∠2=∠3=∠4

Hence, it is proved that AC bisects ∠BCD and ∠BAD.

Similarly, BD will bisect ∠ABC and ∠ADC

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