Question

Parabola y = ax, which passes through the
point (1.2), its focus is ........​

Answer 1

Answer:

Your equation is y^2=4ax

As it passes through (1,2)

we get,. 2^2=4×a×1

=>a=4/4

=>1

So the equation of required parabola is y^2=4x

So, Focus is (a,0) i.e. (1,0)

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Answer 2

Answer:

focus=(a,0). (As the eqn focus lie on +ve x axis)

here the point=(1,

therefore y²=4ax

. 2²=4a×1

. 4=4a

. a=44÷4=

. Foci=(1,

Step-by-step explanation: