Physics, asked by Akshikiski5182, 10 months ago

Paragraph 1 a person crosses a river twice on the same straight path ab (a and b are the two points on opposite bank of the river). River width is d, path ab makes 30 with river flow velocity and the person always swims with speed m/s with respect to water. If it takes t1 time for person to go from a to b and t2 time to come back from b to a

Answers

Answered by ArjunPartha
0

Answer:

v(P,R)=1 ms^-1

it shows that he can swim in Rest water with a Velocity of 1ms^-1

If he swim on this way to a from b

if the velocity of the river is v

then by Velocity Triangles

v=1 cos 30=root (3) /2.

then 1 sin 30=0.5 ms^-1

then by S=ut

d=0.5 × t1

then t1=2d

if he swims b to a

then his Vertical velocity is 1 sin 30=0.5

then horizontal velocity is root(3)/2+v=root(3)

then he will spend t2

d=0.5×t2

then t2=2d

but he goes with river untill goes to the other bank.

so root(3)×2d=2.root(3) d= distance going with the river

Answered by yash6699
1

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