Physics, asked by divesh1554, 8 months ago

" PARAGRAPH 1
Light guidance in an optical fiber can be understood by considering a structure comprising of thin solid glass
cylinder of refractive index n₁ surrounded by a medium of lower refractive index n₂. The light guidance in the
structure takes place due to successive total internal reflections at the interface of the media n₁ and n₂ as shown in
the figure. All rays with the angle of incidence i less than a particular value i???? are confined in the medium of
refractive index n₁. The numerical aperture (NA) of the structure is defined as sin i????"
For two structures namely S₁ with n₁= √45 / 4 and n₂ = 3/2, and S₂ with n₁ = 8/5 and n₂ = 7/5 and
taking the refractive index of water to be 4/3 and that of air to be 1, the correct option(s) is(are)
(A) NA of S₁ immersed in water is the same as that of S₂ immersed in a liquid of refractive index 16/3√15
(B) NA of S₁ immersed in liquid of refractive index 6/√15 is the same as that of S₂ immersed in water
(C) NA of S₁ placed in air is the same as that of S₂ immersed in liquid of refractive index 4/√15.
(D) NA of S₁ placed in air is the same as that of S₂ placed in water

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Answered by chaithanya305
1

Explanation:

I am not posting for points but this question is hard to explain on paper. so please copy the text from here and search on Google. Vist doubt nut page. And there is a solved video of this question.

I saw it,it's easy to understand

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