Question

Paragraph
A small ball is thrown with initial speed u at an angle (with the horizontal) from a smooth horizontal surface. The ball
makes several impacts with the surface. The coefficient of restitution is e. find the total time of flight of the ball.​

Answer 1

Answer:

$\frac{e u 2 \sin (p)}{g}$

Explanation:

Coefficient of restitution is the part of the velocity with which the ball bounces up again in case of a bouncing. It depends on elasticity of the body.

Velocity of the body initially = u

Angle of the body bouncing with the horizontal = p

So, according to the formula,

Final velocity $=v(\text {let})=u \times \sin (p)$

$V-u=a t$

$0-(e u \sin (p))=-g t$

$\frac{-e u 2 \sin (p)}{-g}=t$

So, time required is  $\frac{e u 2 \sin (p)}{g}$