Question

Parallel lines s and t are cut by a transversal, r, as shown. What is the measure of angle 1?

Answer 1

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Answer 2

Answer:

$\angle 1 = 42\degree$

Step-by-step explanation:

$Given \\s\parallel t , \: transversal \: is \: r$

$7x-2 = 6x+18$

/* Exterior alternate angles are equal */

$\implies 7x-6x=18+2$

$\implies x = 20$

$\angle 1 + (7x-2)\degree =180\degree$

/* Linear pair */

$\implies \angle 1 = 180-(7x-2)\\=180-(7\times 20-2)\\=180-(140-2)\\=180-138\\=42\degree$

Therefore,

$\angle 1 = 42\degree$

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