Parallel plate air capacitor of plate area of 100 cm2 and separation 5 mm. A potential difference of 300 V is established between its plates by a battery. Calculate the capacitance and charge on the capacitor.
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1. c=Aε0dc=Aε0d = 100×10−4×8.8×10−125×10−3100×10−4×8.8×10−125×10−3 = 17.6 pF Q = CV= 17.6 × 10-12 × 300 = 5.2 × 10-9 C 2. C = AKε0d=KAε0dAKε0d=KAε0d = 2.6 × 17.6 × 10-12 = 45.76pF.
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