Question

Parallel rays of light with wavelength λ = 500 nm are incident on a slit of width a = 0.2 mm. A diffraction pattern is formed on a screen at a distance D = 2.5 m from the slit. Find the position of the first minimum and the width of the central bright fringe.​

Answer 1

Answer:

Wavelength of light beam, λ = 500 nm = 500 × 10−9 m Distance of the screen from the slit, D = 1 m For first minima, n = 1 Distance between the slits = d Distance of the first minimum from the centre of the screen can be obtained as: x = 2.5 mm = 2.5 × 10−3 m It is related to the order of minima as: Therefore, the width of the slits is 0.2 mm.