Question

parallel sides.
The area of a trapezium of altitude 3 m is 12 m². If one of the parallel sides is 2 m
more than the other, then find the lengths of parallel sides of the trapezium.​

Answer 1

Answer:

let one parallel side be x,, other side = (x+2)m

area = 1/2 (sum of parallel sides) height

1/2(2x+2) 3

3(x+1) = 12m^2

3x + 3 = 12

3x = 9

x=3

so one side = 3m and other side is 5m

Answer 2

Explanation:

let the sides be x then one side be 2+x and other side is x

area of trapezium=1/2*h(sum of both parallel sides)

12=1/2*3(x+2+x)

12=1/2*9x+6

12*2=9x+6

24-6=9x

x=18/9

=2

one side is 2+2=4m

other side =2m