Question

parallelogram ABCD < A =5x-20 & parallelogram ABCD < A =5x-20 & <B = 3x +40.Find the angles of the parallelogram *
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Answer 1

Answer:

Angle A = angle C (opposite angles of a parallelogram are equal)

5x-20=3x+40

5x-3x=40+20

2x=60

x= 60/2

x=30

Hope it helps you.

Answer 2

Answer: x = 20°

Step-by-step explanation:

Given, ABCD is a parallelogram (||gm)

∠A = (3x + 40)°

∠C = (5x - 20)°

∵ Co - interior angle is 180°

∴ ∠C + ∠A = 180°

=> (5x - 20)° + (3x + 40)° = 180°

=> 8x + 20° = 180°

=> 8x = 180° - 20°

=> 8x = 160°

=> x = 20°

∴ The value of x = 20°