Parallelogram ABCD the side a b of length 21 CM BC is of length 20 CM if the diagonal AC AC is of length 29 cm find the area of parallelogram
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you can find area of parallelogram ABCD= triangle(ABC+BCD)
area of ABC=
s=(20+21+29)/2 = 35
area = root (35×15×14×6) =5×7×2×3 = 210 cm^2
area of ABC = area of BCD
SO 2×ABC
2×210 cm^2
area of parallelogram =420cm^2
area of ABC=
s=(20+21+29)/2 = 35
area = root (35×15×14×6) =5×7×2×3 = 210 cm^2
area of ABC = area of BCD
SO 2×ABC
2×210 cm^2
area of parallelogram =420cm^2
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