Parallelogram GRAM with GR=AM=5cm,RA=MG=6.2 cm and angle R=85°.
I want this answer with steps-of-construction and with diagram also with labeling please.
Answer it please.
Answers
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Q. 2
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Class 8th
AP - Mathematics
3. Construction of Quadrilaterals
Answer
GIVEN : In Parallelogram GRAM,
GR = AM = 5 cm
RA = MG = 6.2 cm
∠R = 85o
PROCEDURE :
Step 1 : draw a rough sketch of the parallelogram GRAM and mark the given measurements.
Since the given measurements are not sufficient for construction , we shall find the required measurements using the properties of the parallelogram.
As opposite angles of parallelogram are equal so , ∠R = ∠M = 85o and as the consecutive angles are supplementary so , ∠G = 180° - 85° = 95°.
Thus ∠G = ∠A = 95°.
Answer:
GIVEN : In Parallelogram GRAM,
GR = AM = 5 cm
RA = MG = 6.2 cm
∠R = 85o
PROCEDURE :
Step 1 : draw a rough sketch of the parallelogram GRAM and mark the given measurements.
Since the given measurements are not sufficient for construction , we shall find the required measurements using the properties of the parallelogram.
As opposite angles of parallelogram are equal so , ∠R = ∠M = 85o and as the consecutive angles are supplementary so , ∠G = 180° - 85° = 95°.
Thus ∠G = ∠A = 95°.
Step 2 : construct ΔGRA using SAS property of construction model with GR = 5cm , ∠R = 85o and RA = 6.2 cm.
Step 3 : construct ∠G = 95° and draw GY || RA.
Step 4 : construct ∠A = 95° and draw AN to meet GY at M.
GRAM is the required quadrilateral (ie. Parallelogram).