Question

Parallelogram PQRS with PQ=4.5cm, QR=3cm and <RQP=60°?​

Answer 1

Step-by-step explanation:

1. Construct the line segment PQ of length 4.5 cm.

2. At Q, construct 60° with compass. Extend a line segment of length 3 cm such that it cuts the arc of 60°. Name the point as R.

3. The adjacent angles of a parallelogram are supplementary. Angle P = 180° - 60° = 120°.

4. At P, construct 120° with compass. Extend a line segment of length 3 cm such that it cuts the arc of 120°. Name the point as S.

5. Join R and S. PQRS is the required parallelogram.

Answer 2

Answer:

Step-by-step explanation:

1.  Draw a line segment PQ = 4.5 cm

2. Take a compass and keeping Q as a centre construct an angle of 60 degrees.

3. Now take the radius of 3 cm, draw an arc on the 60-degree angle line. The intersection point of the 3 cm arc and 6 degrees will be R.

4. As per the supplementary property of a parallelogram, SPQ + PQR = 180. Hence draw an angle of 120 degrees on point P.

5. Now draw an arc of 3 cm and mark it as S

6. Join PQRS to form a parallelogram