Question

parameter of rectangle is 24 m of length of a rectangle is metre more than its of breadth find b
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Answer 1

Answer:

then b = 11,10,9,8,7,6,5,4,3,2,1

Answer 2

Step-by-step explanation:

Dimensions of a rectangle :

Let length = l m,

breadth = b m,

/* According to the problem given */

Perimeter (P) = 24\:mPerimeter(P)=24m

$\implies 2(l+b) = 24 \:m⟹2(l+b)=24m$

/* On Dividing bothsides by 2 , we get */

$\implies l + b = 12⟹l+b=12$

l = 12 - b \: ---(1)l=12−b−−−(1)

$\begin{gathered} And \\ Area = 27 \: m^{2} \end{gathered}$

$\implies l \times b = 27⟹l×b=27$

$\implies (12-b)\times b = 27 \: [From \: (1) ]⟹(12−b)×b=27[From(1)]$

$\implies 12b - b^{2}$

$\implies b^{2}$

/* Splitting the middle term,we get */

$\implies b^{2}$

$\implies b(b-3) - 9(b-3) = 0⟹b(b−3)−9(b−3)=0$

$\implies ( b -3)( b - 9) = 0⟹(b−3)(b−9)=0$

$\implies b - 3 = 0 \:Or \: b - 9 = 0⟹b−3=0Orb−9=0$

$\implies b = 3 \:Or \: b = 9⟹b=3Orb=9$

/* Substitute b value in equation (1), we get */

case 1:

If b = 3 then l = 12 - 3 = 9 m ;

Case 2:

If b = 8 then l = 12 - 9 = 3 m .

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