Question

Parents are heterozygous tall . Arrive at the probable offspring off springs on cross between two such parents​

Answer 1

Explanation:

If we consider a cross between AaBbCc, the value of n = 3.

If we consider a cross between AaBbCc, the value of n = 3.The maximum number of possible gametes is 2 raised to 'n'.

If we consider a cross between AaBbCc, the value of n = 3.The maximum number of possible gametes is 2 raised to 'n'.Value of n = 3.

If we consider a cross between AaBbCc, the value of n = 3.The maximum number of possible gametes is 2 raised to 'n'.Value of n = 3.Thus, maximum 2x2x2 = 8 gametes are produced. This makes it clear that maximum offspring produced is 8x8 = 64. The possibility of a recessive genotype in this combination of Punnet square is 1/64. This means that one out of 64 offspring produced will have aabbcc genotype.