Math, asked by kmohan, 1 year ago

park in the shape of quadrilateral ABCD has C=90°. ab=18 m bc=24 M ,cd equals to 10 M and ad is equal to 16 m how much area does it occupy

Answers

Answered by Tamash
159
approx area = 262 m²

hope it is helpful for u...
Attachments:
Answered by vaduz
32

Answer:200m²  


Step-by-step explanation:

by drawing quadrilateral ABCD, we can easily tell that the quadrilateral is trapezoid.

as we know the formula of area of trapezoid

A =\frac{a+b}{2}*h\\\\A=\frac{AD+BC}{2}*CD\\\\A=\frac{16+24}{2}*10\\\\A=200

so the area of trapezoid is 200m²  


Similar questions