Parnika walks 32 km partly at the speed of 7kph and remaining at the speed of 6 kph. If she had walked alternately she would have covered 1 km more in the same time. Find how much time she walk at the speed of 7 kph and how much time she walk at the speed of 6 kph?
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V1=7kph
v2=6kph
t1= time she walk at the speed of 7 kph
t2=time she walk at the speed of 6 kph
s=v*t
32=v1t+v2t
32=7*t1+6*t2 equa 1
33=v1*t1+v2*t2
33=6*t1+7*t2 equa 2
Equating both equations
(32-6t2) / 7 = (33-7t2) / 6
192-36t2=231 - 49t2
-39=-13t2
3=t2
33=6t1 + 21
12=6t1
2=t1
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