Question

Parnika walks 32 km partly at the speed of 7kph and remaining at the speed of 6 kph. If she had walked alternately she would have covered 1 km more in the same time. Find how much time she walk at the speed of 7 kph and how much time she walk at the speed of 6 kph?

Answer 1

V1=7kph

v2=6kph

t1= time she walk at the speed of 7 kph  

t2=time she walk at the speed of 6 kph  

s=v*t

32=v1t+v2t

32=7*t1+6*t2 equa 1

33=v1*t1+v2*t2

33=6*t1+7*t2 equa 2

Equating both equations

(32-6t2) / 7 = (33-7t2) / 6

192-36t2=231 - 49t2

-39=-13t2

3=t2

33=6t1 + 21

12=6t1

2=t1