Part 1: Name two elements that have the same properties as sodium (Na). (4 points)
Part 2: Determine the number of protons, electrons, and neutrons present in an atom of calcium (Ca). Explain how you determined your answer using complete sentences. (6 points) (10 points)
Answers
Answer:
part 1 potassium and rubidium
part 2. EC of Ca is 2,8,8,2 no. of protons present is 20 thats determine the atomic no. and same no of electron and neutrons present
The answers are given below:
Answers to Part 1:
• The two elements that have the same properties as Sodium are: Potassium and Rubidium.
• Reason: It is because the elements that are present in the same group shares similar properties. Since Sodium, Potassium and Rubidium are in the same group, they exhibit similar properties.
Answers to Part 2:
• The number of protons in an atom of Calcium is 20
The number of electrons in an atom of Calcium is 20
And number of neutrons in an atom of Calcium is 20
Explanation:
Determining number of electrons:
The number of electrons in an atom is equal to the atomic number of that atom.
Therefore, since Calcium has 20 as atomic number, hence it's number of electrons is also 20
Determining number of protons:
The number of protons of an atom is exactly same as the number of electrons of that atom.
Hence, Calcium has 20 protons (same as the number of electrons)
Determining number of neutrons:
Number of neutrons is Atomic mass minus atomic Number.
Therefore,
Number of neutrons of Ca = Atomic mass of Ca - Atomic number of Ca
= 40 - 20
= 20
Hence, number of neutrons in Ca is 20
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