PART 1
Which copper wire has the lowest resistance?
A 1 meter long 1 millimeter diameter wire
B 0.5 meter long, 1 millimeter diameter wire
C 0.5 meter long, 0.5 millimeter diameter wire
D 1 meter long, 0.5 millimeter diameter wire
What happens to the resistance of a metal when the temperature is increased?
A Increase
B Decrease
C Stay the same
D Vary randomly
The length of a certain conductor of resistance 100Ω is doubles and its cross sectional area doubled. Its new resistance is
A 50 Ω
B 100 Ω
C 200 Ω
D 400 Ω
If the diameter of a metallic wire is reduced to one half, keeping the length of the wire constant. The new resistance of the wire will be:
A four times the original
B one-fourth of the original
C half of the original wire
D double of the original wire
With increase in temperature, the insulating property of a material
A weakens
B remains unchanged
C can either weakens or gains
D gains
As compare to long copper wire, a short copper has
A lower conductivity
B higher conductivity
C same conductivity
D lower resistivity
The reciprocal of resistance is
A resistivity
B reactance
C conductance
D conductivity
A wire of 5 Ω resistance is drawn out so that its new length is two times the original length. If he resistivity of the wire remains the same and the cross sectional area is halved, the new resistance is
A 40 Ω
B 20 Ω
C 10 Ω
D 5 Ω
A wire P has the same diameter and half the length of wire Q of similar material. The ratio of the length of the resistance of P to that of Q is
A 1:2
B 1:4
C 2:1
D 4:1
The resistance of a 5.0 m uniform wire of cross sectional area 0.2 x 10-6 m2 is 0.425 Ω. What is the conductivity of the material of the wire?
A 1.7 x 10-8 Ω-1m-1
B 5.8 x 107 Ω-1m-1
C 1.7 x 107 Ω-1m-1
D 5.8 x 10-8 Ω-1m-1
PART 2
A galvanometer with full scale deflection of 1.5 x 10-3 A has a resistance of 50 ohm. With the aid of a suitable circuit diagram, determine the resistance required to convert it into a voltmeter reading up to 1.5 V
A galvanometer of full scale deflection of 10 mA with a coil resistance of 20 ohm is to be converted to an ammeter with a full scale deflection of 10 A. Draw the circuit diagram for the conversion and calculate the value of resistance required
A milliammeter with full scale deflection of 10 mA has an internal resistance of 5 Ω. Draw a circuit diagram and calculate the resistance require to convert it to an ammeter with full scale deflection of 1A
Determine the value of the series resistance required to convert the galvanometer below to a voltmeter with full scale range deflection of 15V
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Answers
Answered by
2
Answer:
Given, Diameter=0.5mm,resistivity=1.6×10−8Ω−m,resistance=10Ω
we know that R=ρA1⇒1=ρRA
Where A is the area of the cross-section,
=1.6×10−810×3.14×(20.0005)2=122.7m
Thus the length of the wire is 122.7m
Answered by
2
Answer:
122.7 meter
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