Question

Part 11
P
Given
: Any point equidistant from sides of an angle is on the bisector of the angle.
: A is a point in the interior of ZPQR.
seg AC I ray QR seg AB I ray QP
and AB = AC

To prove: Ray QA is the bisector of ZPQR.
That is <BQA= <CQA
Fig. 3.43
Proof : Write the proof using proper test of congruence of triangles.​

Answer 1

Answer:

Solution-

we need to show BP=CP

in right angles △ABP

sinα=APBP...(i)

in right angled △ACP 

sinα=APCP...(ii)

from (i) & (ii)

APBP=APCP

BP=CP

Hence Proved.

Step-by-step explanation:

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