Question

PART 3
Date:150920 sig, er det
VUA
S69.255653
Student B.Amutha
CRT-1
SA
Find the value of even + Odd +even (20times)​

Answer 1

Answer:

so as it is repeated 20 times

there will be 10 odd and 10 even

now 10 is a even number

so even ×odd = even

even × even = even

even + even = even

so the answer will be even