Math, asked by pushpinder1966, 10 months ago

PART-C
Adice is thrown 80 times. If the probability of having an even number is
7/10 then how many times an odd number appears on dice ?​

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Answers

Answered by sahilkund42
4

Answer:

so,

let s be the sample space

n(s) =80

let A be the event of getting even number

p(A) =n(A) /n(s)

7/10= n(A) /80

n(A) = 7/10*80

= 7*8

=56

let B be the event of getting odd number

n(B) = n(s) - n(A)

= 80 - 56

= 24

so, 24 times an odd number appears on dice is thrown

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