Question

PART-II
II. Answer all the questions.
21. If acos -bsin=c Show that asin + bcos0= +- √a²+b²- c²​

Answer 1

Answer:

asin +bcos = c

taking square both sides,

(asine+bcos) = c²

asine+ bcos +2absine.cos c-(1)

Let acose - bsine =x

Squaring both sides

(acose- bsin)? = x2

acose+ b?sin?e -2absine.cose = x*-(2)

Add equation (1) and (2),

asin0+b?cos^0 +2abine.cos0+ a?cos^0 +

bsine-2absine.cose = c2+x

la + bJcos e + (a +b)sin?e = c +x*

{a2+bsin^e + cose]=c2+x

a+b) =c +x*[" sin?x + cosx=1]

a2+bc) = x²

Take square root both sides,

+/-root a2+b2-c2=x

Hence, acose - bsine =

Root a2+b2 - c^2.

Answer 2

Answer:

above answer is correct.......