Question

Part of one row of the periodic table is shown.

4 blue boxes in a row. The first has S n at the center and 50 above with tin and 118.71 below. The second has S b at the center and 51 above with antimony and 121.76 below. The third has T e at the center and 52 above with tellurium and 127.60 below. The fourth has I at the center and 53 above with iodine and 126.90 below.

Which element’s atoms have the greatest average number of neutrons?

tin (Sn)
antimony (Sb)
tellurium (Te)
iodine (I)

Answer 1

Answer:

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Explanation:

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Answer 2

Answer:

tin (Sn)

Explanation:

because it is the right answer