Question

Part of the proceeds from a garage sale was ​$410

worth of ​$10

and ​$20

bills. If there were 5

more ​$10

bills than ​$20

​bills, find the number of each denomination.

Answer 1

Answer:

be the number of the $20 dollars bills.

Then the number of the $10 dollars bills is (x+2), according to the condition.

The money equation is

20x + 10*(x+2) = 410

Simplify and solve for x.

20x + 10x + 20 = 410

30x = 410-20 = 390 ====> x = 390%2F30 = 13.

Answer. 13 of the $20-dollars bills and 13+2 = 15 of the $10-dollars bills.

Check. 20*13 + 10*15 = 410 dollars. ! Correct !

Step-by-step explanation:

Bro plz mark as the brainliest al മലയാളി frm ആലപ്പുഴ ✌️ follow me