Question

Parthiv tells his son aarav that five years ago his age was seven times the age of his son that time. Further stated that ten years from now his age would be two and a half times than his son.Find the present age of both of them

Answer 1

Answer:

Parthiv's age = 40 years and his son's age = 10 years.

Step-by-step explanation:

Answer 2

The present age of his son is 10 years and his father is 40 years.

Step-by-step explanation:

Let the present age of his son be 'x'

Let the present age of father be '7(x-5)+5=7x-35+5=7x-30'

After 10 years,

Age of son = x+10

Age of father = 7x-30+10=7x-20

According to question, it becomes,

$7x-20=2\dfrac{1}{2}(x+10)\\\\7x-20=\dfrac{5}{2}(x+10)\\\\2(7x-20)=5(x+10)\\\\14x-40=5x+50\\\\14x-5x=50+40\\\\9x=90\\\\x=\dfrac{90}{9}\\\\x=10$

So, the present age of his son = 10 years

present age of father = $7x-30=7(10)-30=70-30=40$

Hence, the present age of his son is 10 years and his father is 40 years.

# learn  more:

Five years ago, the age of aman was seven times the age of his son. The age of man will be three times the age of his son in five years from now. The present age of the man and his son, respectively, are

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