Question

partial differentiation of x + y + z = log z​

Answer 1

Answer:

sorry I have not answered sorry but.i have trip cholate ka lo answered mil jata ga

Answer 2

The partial derivatives of x + y + z with respect to x, y, and z are 1, 1, and 1/z, respectively.

Given :

x + y + z = log z​

To find :

Partial differentiation with respect to x, y, z.

Solution:

Partial derivative with respect to x:

$d(x + y + z)/dx = d(x)/dx + d(y)/dx + d(z)/dx\\ d(x + y + z)/dx = 1 + 0 + 0$

Partial derivative with respect to y:

$d(x + y + z)/dy = d(x)/dy + d(y)/dy + d(z)/dy \\d(x + y + z)/dy = 0 + 1 + 0.$

Partial derivative with respect to z:

$d(x + y + z)/dz = d(log z)/dz \\d(x + y + z)/dz = 1/z$

Therefore, the partial derivatives of x + y + z with respect to x, y, and z are 1, 1, and 1/z, respectively.

#SPJ3