Question

Partial pressure of solvent in solution of non-volatile solute is given by equation.
a) p=x₂p°
b) p°=xp
c) p=x₁p°
d) p°=x₁p

Answer 1

if x1 is mole fraction of solute and x2 the mole fraction of solvent then, answer is

 (a) p = x₂p⁰

Answer 2

if x1 is mole fraction of solute and x2 the mole fraction of solvent then it is p = x₂p⁰.

Therefore it can be calculate with its own values without meeting any trouble of it hope this answer is helpful for the major student who are not clear and not able to find out the answer for this question.