Question

partical has an initial velocity 5 and an accelerationof 0.5. its speed after 10 seconds is

Answer 1

Answer:

7(2)^1/2

given u=3i+4j

a=0.3i+0.4j

t=10s

u=v-at

3i+4j=v-(0.3i+0.4j)10

3i+4j=v-(3i+4j)

3i+4j+3i+4j=v

3+4(i+j)=v

7(i+j)=v

magnitude of v=root of 7^2+7^2

=root of 98

=7(2)^1/2

Explanation:

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Answer 2

Answer:

to find initial velocity

u=5m/s

t=10sec

accň =0.5m/s²

v =u+at

=5 +0.5*10

= 5+ 5

=10 m/s

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