Question

Particle ‘1’ of mass ‘m’ initially moving in the positive x-direction with speed V1i collides with the particle ‘2’ of mass m2 = m/3 moving in opposite direction of particle ‘1’ with unknown speed V2i as shown in figure. Assume no external force is acting upon the particle and don’t assume the elastic collision. After the collision, the particle ‘1’ moves in negative y-direction with speed V1f = V1i /2 and particle ‘2’ moves at angle 45o with the positive xdirection. Determine the speed of particle ‘2’ before and after collision and confirm collision is elastic or inelastic? ​

Answer 1

Answer:This may help you

Explanation:

Total momentum of system before collision=m 1v1 ↑+0

⇒ p->=m1v1↑

⇒( p )=m 1 v 1

​Hence, the answer is m1v1.

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