particle
3. A particle moves 20 m in 3rd second and 30 m in 5th second of its journey
What will be the distance covered by the body in 4 s after 6th second?
Anarticle is initially at rest. It starts moving with a constant acceleration
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Answer:
A particle moves with constant acceleration along a straight line starting from rest. The percentage increase in its displacement during the 4th second compared to that in the 3rd second is:
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ANSWER
The displacement of the particle in nth second S
n
=u+
2
1
a(2n−1)
where all the symbols have their usual meaning.
Given : u=0
⟹S
n
=
2
1
a(2n−1)
Thus displacement in the 3rd second S
3
=
2
1
a(2×3−1)=
2
5a
Displacement in the 4th second S
4
=
2
1
a(2×4−1)=
2
7a
Percentage increase in the displacement
S
3
ΔS
×100=
S
3
S
4
−S
3
×100
S
3
ΔS
×100=
2
5a
2
7a
−
2
5a
×100=40
Thus percentage increase in the displacement is 40 %
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