Question

Particle A and B are free to move along parallel paths. B is moving at a constant velocity of 10 m/s and A starts moving at the moment B passes it. If A accelerates at 1 m/s2 for 5 s and then travels at a constant velocity. Find the distance between A and B 10s after B passes A

Answer 1

Answer:

62.5 m

Explanation:

B is moving at a constant velocity of 10 m/s

Distance Travelled by B in 10 Sec after B Passes A

= 10* 10 = 100 m

A Starts from Rest

so initial Velocity = 0

Velocity after 5 sec using V = U + at

V = 0 + 1*5 = 5 m/s

Distance Covered in 5 sec

S = Ut + (1/2)at²  = 0 + (1/2)(1)5² = 25/2

Now it moves with conatant Velocity of 5 m/s

Distance covered in next 10 -5 = 5 sec

= 5 * 5 = 25 m

Total Distance Covered by A = 25/2 + 25  =  75/2 m

the distance between A and B = 100 - 75/2  =  125/2 m

= 62.5 m