Question

particle A has velocity = 8i , particle B has velocity 4i +4√3 j . "magnitude" of relative velocity is??

Answer 1

Answer:

The concentration of the reactant plays an important role in the rate of a reaction. As the concentration of the reactant increases, the number of reacting molecules increases. Because of the increase in the number of molecules, the number of collisions also increases as a result the rate of the reaction increases.

Answer 2

We have to find magnitude of relative velocity of particles. if velocity of particle A is 8 i and velocity of particle B is 4 i + 4√3 j.

Solution : velocity of particle A, $V_A$ = 8i

velocity of particle , $V_B$ = 4 i + 4√3 j

relative velocity of particle A with respect to particle B is $V_A-V_B$

= 8i - (4i + 4√3 j)

= 4i - 4√3 j

magnitude of relative velocity of particle A with respect to B, |$V_{AB}$| = √{(4)² + (-4√3)²}

= √(16 + 48) = √64 = 8 m/s

similarly, relative velocity of particle B with respect to A, $V_{BA}$ = $V_B-V_A$

= (4i + 4√3j) - 8i

= -4i + 4√3j

magnitude of relative velocity of particle B to A, $|V_{BA}|$ = √{(-4)² + (4√3)²} = 8

Therefore the magnitude of relative velocity is 8 unit.