Question

particle A is moving towards north with an acceleration of 5 ms and particle B is moving north-east i
direction with an acceleration of 5√2m/s^2.Find relative acceleration of particle A with respect to
particle B.

Answer 1

Given :

The acceleration of particle A = 5m/s²

The acceleration of particle B = 5√2m/s²

To Find :

The relative acceleration of particle A w.r.t B

Solution :

• Let us consider east as  +ve X-direction and north as +ve Y-direction

• Acceleration of particle A = 5i

• Acceleration of particle B = 5√2 (i+j /√2) = 5i + 5j

• Relative acceleration = Acceleration of particle A - Acceleration of particle B

                     = 5j - (5i + 5j)

                     = -5i

The relative acceleration of particle is 5m/s² towards east