Question

Particle A is moving with velocity (6î +109) m/s and particle B is moving with velocity (3î +6j) m/s. Magnitude of velocity of A w.r.t. B is ​

Answer 1

Answer:

2

​

 

1

​

m/s  

2

 N-W

Explanation:

Initial velocity =v  

1

​

=5m/s seast wards.

then after time t=10 sec

towards east =5m/s

v  

2

​

=5m/s north wards.

towards east =5m/s

V resultant =  

v  

1

2

​

+v  

2

2

​

 

​

 

=  

25+25

​

 

=5  

2

​

 

​

 

acceleration a=v=velocity/time

=  

10

5  

2

​

 

​

=  

2

2

​

 

​

×  

2

​

 

2

​

 

​

 

=  

2

​

 

1

​

towardsn−w

​