Particle
A is on x-axis at x=+6m and
moving towards the origin with a
speed of 1.5m/s. Another particle B is
also on x-axis at x=-4m which is
also moving towards the origin, the
relative velocity of an with respect to B is
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Answer:
Position is given as x=a+bt2=8.5+2.5t2
Position at t=2 s, x2=8.5+2.5(2)2=18.5 m
Position at t=4 s, x1=8.5+2.5(4)2=48.5 m
Displacement S=x2−x1=48.5−18.5=30 m
Time taken t=4−2=2 s
Average velocity Vavg=tS=230=15 m/s
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